52. Solution to Chemistry Problem
Content: 2.docx (16.32 KB)
Uploaded: 29.03.2025
Positive responses: 0
Negative responses: 0
Sold: 0
Refunds: 0
$1.32
2. The heat of the reaction Pb Hg2Cl2 = PbCl2 2 Hg is 22710 cal at 298 K. The EMF of the element operating due to this reaction increases by 0.000145 V with an increase in temperature by 10. Determine the EMF of the element and the change in entropy of the reaction at 298 K.
If you cannot open the file or have any problems, do not rush to leave a negative review! Contact me and I will quickly help you solve the problem. After purchasing, please leave a positive review of the product :)
No feedback yet