6. Determine the enthalpy of formation of diborane B2H6(g) at T = 298 K from the following data: B2H6(g)+3 O2g)→B₂O₃(s) +3H2O(l), ΔH° =-2035.6 kJ•mol⁻¹ 2B(s)+3/2 O2(g) → B2O3s), ΔH2° =-1273.5 kJ•mol⁻¹ H2(g)+1/2O₂(g)→H₂O(g), ΔH3°=-241 .8 kJ•mol⁻¹
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