Determine what mass of aluminum will be released at the cathode in dt=10 hours during the electrolysis of Al2(SO4)3, if during this time the current through the electrolyte decreases uniformly from I1=1.5 A to I2=0.5 A. Atomic weight of aluminum M =27, Avogadro's number Na=6 • 1023 mol-1, electron charge e=1.6•10-19 Cl.
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