Triangle ABC moves in space in such a way that at a given moment in time the speed of point A is directed along side AB and vA = 3.0 m/s: and the speed of point B is directed along side BC and vB = 4.0 m/s. Angle ABC is acute, AB=2.6 m: BC=3.0 m. Determine the speed of point C.
Short solution. Format gif
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