A potential difference of U = 5 V is applied to the electrodes of the discharge tube, the distance between them is l = 10 cm. The ionizer creates n = 106 ion pairs per second in 1 cm3 of tube gas. Ion mobility u+ = 3·10–2 m2/(B·s), u– = 2·10–2 m2/(V·s). Find the current density in the tube. Also determine what part of the total current is created by the movement of positive ions.
Detailed solution. Format doc(word)
No feedback yet