43. Solving a chemistry problem
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373. The reaction is expressed by the schemes:
KBrO MnCl2 KOH = KBr MnO2 KCl H2O,
Co HNO3razb \u003d Co (NO3) 2 NO H2O.
Write electronic equations. Arrange the coefficients in the reaction equations. For each reaction, indicate which substance is the oxidizing agent, which is the reducing agent; which substance is oxidized and which is reduced.
KBrO MnCl2 KOH = KBr MnO2 KCl H2O,
Co HNO3razb \u003d Co (NO3) 2 NO H2O.
Write electronic equations. Arrange the coefficients in the reaction equations. For each reaction, indicate which substance is the oxidizing agent, which is the reducing agent; which substance is oxidized and which is reduced.
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