49. Solving a chemistry problem
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Based on the benzene adsorption isotherm, determine the specific surface area of the adsorbent (T = 293K, S0 = 49 10-20 m2). The volume of adsorbed gas is reduced to normal conditions:
p/ps……………………………………… 0.10 0.15 0.20 0.25 0.30 0.35
a 102, m3/kg……………………………… 1.15 1.37 1.55 1.71 1.86 1.99
p/ps……………………………………… 0.10 0.15 0.20 0.25 0.30 0.35
a 102, m3/kg……………………………… 1.15 1.37 1.55 1.71 1.86 1.99
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