92. Solving a chemistry problem

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4. Calculate the enthalpy of reaction under standard conditions: C2H6(g) 7/2 O2(g) ↔ 2CO2(g) 3H2O(g);
ΔHo6H2O=-241.8 kJ/mol; ΔNobCO2=-393.5 kJ/mol; ΔHobC2H6=-89.7 kJ/mol.

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