Content: 73.rar (11.09 KB)
Uploaded: 19.05.2022

Positive responses: 0
Negative responses: 0

Sold: 0
Refunds: 0

$0.92
73. How much do you need to add a solution of KMnO4 with W (KMnO4) = 4.4% to 4850 cm3 of a solution with C (1/5 KMnO4) = 0.1000 mol / dm3 and a correction factor F = 0.9823 to get exactly C ( 1/5 KMnO4) = 0.1000 mol / dm3.
No feedback yet