Content: 00096.png (32.12 KB)
Uploaded: 21.11.2021

Positive responses: 0
Negative responses: 0

Sold: 1
Refunds: 0

$0.87
The movement of a pilot during ejection from a jet plane can be approximately described by the formula S = 3.7t3 lnt - 19t m. Determine the speed and acceleration of the pilot 2 s after the ejection.
Detailed solution with a brief record of the conditions, formulas and laws used in the decision, the conclusion of the calculation formula and the answer.
If you have any questions about the decision, write. I will try to help. File in image format.
No feedback yet

Similar items